Answer:
[tex]\text{Standard Deviation}=0.76[/tex]
Step-by-step explanation:
The average January surface water temperatures in °C of Lake Michigan from 2000 to 2009 are,
[tex]5.07, 3.57, 5.32, 3.19, 3.49, 4.25, 4.76, 5.19, 3.94,4.34[/tex]
The mean [tex](\overline{x})[/tex] and variance [tex](\sigma^2)[/tex] are,
[tex]\overline{x}=\sum_{i=1}^{10}a_i=4.312[/tex]
[tex]\sigma^2=\sum _{i=1}^n\dfrac{\left(x_i-\bar{x}\right)^2}{n-1}=0.577[/tex]
Standard deviation is the square root of variance.
i.e [tex]\text{Standard Deviation}=\sigma=\sqrt{\sigma ^2}[/tex]
[tex]\text{Standard Deviation}=\sqrt{0.577}=0.76[/tex]
