we know that
the volume of the sphere is equal to
[tex]V=\frac{4}{3}\pi r^{3}[/tex]
where
r is the radius of the sphere
In this problem
we have the diameter
[tex]D=4\ cm\\\\ r=\frac{D}{2}\\\\r=2\ cm[/tex]
substitute the value of the radius in the formula above
[tex]V=\frac{4}{3}\pi 2^{3}[/tex]
[tex]V=\frac{32}{3}\pi\ cm^{3}[/tex]
therefore
the answer is
the volume of the sphere is equal to
[tex]V=\frac{32}{3}\pi\ cm^{3}[/tex]
