The product [tex]6(x^2-1)[/tex] multiplied by [tex]\frac{6x-1}{6(x+1)}[/tex] is given by (d) (x-1)(6x-1).
What is Algebraic expression?
An mathematical term involving variable, numbers or other mathematical quantities is called as Algebraic Expression.
We know that, [tex]a^2-b^2=(a+b)(a-b)[/tex]
In this problem given the expressions are, [tex]\frac{6x-1}{6(x+1)}[/tex] and
[tex]6(x^2-1)=6\{x^2-1^2\}=6(x+1)(x-1)[/tex]
On multiplying the given expression we get,
[tex]6(x^2-1)\cdot\frac{(6x-1)}{6(x+1)}=6(x+1)(x-1)\cdot\frac{(6x-1)}{6(x+1)}[/tex]
[tex]=(x-1).(6x-1)[/tex], eliminating the like terms
So the product is (x-1)(6x-1)
Hence the correct option is (d).
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