Respuesta :
Answer:
B 0
A AB A0
0 B0 00
Explanation:
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A parent of phenotype A and heterozygous genotype (A0) can have two possible gametes A and 0.
A parent of phenotype B and heterozygous genotype (B0) can have two possible gametes B and 0.
When crossing the two parents we can see that the four blood types are possible in equal probability.
Genotype A0: phenotype A
Genotype B0: phenotype B
AB genotype: AB phenotype
Genotype 00: Phenotype 00.
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From the result of the Punnnett square, parents who are heterozygous for type A and type B blood can have children with any of the four human blood types.
Why can parents who are heterozygous for type A and type B blood have children with any of the four human blood types
Parents who are heterozygous for type A and type B blood have the following genotype; AO and BO
Using a Punnett square, the possible offspring are as follows:
Gametes: A O
B---> AB BO
O ---> AO OO
From the result of the Punnnett square above, the offspring produced are AB, BO, AO, and OO which represents the four human blood groups.
Therefore, parents who are heterozygous for type A and type B blood can have children with any of the four human blood types.
Learn more about human blood groups at: https://brainly.com/question/2188574