Answer:
[tex]x=6\°[/tex]
Step-by-step explanation:
we know that
The sum of the internal angles of a kite is equal to [tex]360\°[/tex]
so
In this problem we have
[tex]90\°+90\°+(18x-2)\°+(12x+2)\°=360\°[/tex]
[tex](18x-2)\°+(12x+2)\°=360\°-180\°[/tex]
[tex]30x=180\°[/tex]
[tex]x=6\°[/tex]
