bextem
contestada

Compare the area of a rectangle whose sides are 3 and 1/9 inches by 4 and 2/3 inches to a rectangle whose sides are 3 and 2/3 inches by 4 and 1/5 inches. Which is greater? By how much? Answer in inches.

Respuesta :

Area of a rectangle 1=L*W
Area=31/9*4 2/3
Area=28/9*14/3=14.518 inches^2

Area of a rectangle 1=l*w
area=11/3*21/5
Area=15.4

Area of a rectangle 2 is more by 0.88 inche^2
texaschic101
A = L * W

3 1/9 by 4 2/3....

A = (3 1/9)(4 2/3)
A = 28/9 * 14/3
A = 392/27  (or 14 14/27)

3 2/3 by 4 1/5

A = (3 2/3)(4 1/5)
A = 11/3 * 21/5
A = 77/5 (or 15 2/5)

The second one (with the dimensions of 3 2/3 by 4 1/5) is greater

15 2/5 - 14 14/27 = 119/135 (or 0.88 inches)