Respuesta :

bcalle
20y^2 + 3y - 2
20* -2 = -40
factors of -40 that subtract to give you 3
8 * -5 = -40
8 + (-5) = 3
20y^2 -5y + 8y -2
5y( 4y - 1) +2(4y -1)
(4y - 1) ( 5y + 2)
isyllus

Answer:

[tex] (5y+2)(4y-1)[/tex]

Step-by-step explanation:

Given: [tex]20y^2+3y-2[/tex]

Factor: Middle term splitting

We have to factor the quadratic equation.

[tex]\Rightarrow 20y^2+3y-2[/tex]

[tex]\Rightarrow 20y^2+8y-5y-2[/tex]

Make group and factor each group

[tex]\Rightarrow (20y^2+8y)-(5y-2)[/tex]

[tex]\Rightarrow 4y(5y+2)-1(5y+2)[/tex]

[tex]\Rightarrow (5y+2)(4y-1)[/tex]

Hence, The factors are [tex] (5y+2)(4y-1)[/tex]

Please see the attachment for grid factor.

Ver imagen isyllus