Respuesta :
13+2(5c-2)=29
(2*5c) and (2*-2)
13+10c-4=29
add 4
13+10c= 33
subtract 13
10c=20
divide by 10
c=2
(2*5c) and (2*-2)
13+10c-4=29
add 4
13+10c= 33
subtract 13
10c=20
divide by 10
c=2
So you want to start by subtracting (13) from both sides...
1) 2(5c−2)=29−132) 2(5c−2)=163) 5c−2=16/2
4) 5c−2=85) 5c=8+26) 5c=107) c=5/108) this leaves you with C=2
1) 2(5c−2)=29−132) 2(5c−2)=163) 5c−2=16/2
4) 5c−2=85) 5c=8+26) 5c=107) c=5/108) this leaves you with C=2