Respuesta :
The paper's smallest dimensions are height=8.660in and width=17.321in.
What are dimensions?
In physics and mathematics, the dimension of space is the smallest set of coordinates needed to specify any point within a mathematical space.
A line has a dimension of one because only one coordinate is needed to specify a point on a line, such as a point at 5 on a number.
So, we have:
Area = 150in²
Side margin = 1 in
Top and Bottom Margin = 2 in
To obtain the smallest dimensions, calculate as follows:
The printed material's area is:
Area = l*w
A1 = h*w
A1 should be changed to 150:
150 = h*w
h = 150/w
The complete paper's topic is:
Area = l*w
A2 = (w+2+2)*(H+1+1)
A2 = (w+4)*(H+2)
For H, substitute 150/W:
A2 = (w+4)*(150/w+2)
A2 = w(150/w+2) + 4(150/w+2)
A2 = 150 + 2w + 600w + 8
A2 = 2w = 600/w + 8 + 150
A2 = 2w = 600/w + 158
Calculate a difference with regard to w and set the outcome to 0:
A'2 = 2-600/w²+0
A'2 = 2-600/w²
0 = 2 - 600/w²
2 = 600/w²
2*w² = 600
w² = 600/2
w² = 300
w = 17.321
Remember that:
h = 150/w
h = 150/17.321
h = 8.660
Therefore, the paper's smallest dimensions are height=8.660in and width=17.321in.
Know more about dimensions here:
https://brainly.com/question/19819849
#SPJ4
