The molarity of the solution is 0.411 M.
given that :
volume = 40.30 mL = 0.040 L
molarity = 0.1823 M
moles = molarity × volume
= 0.1823 × 0.040
= 0.0072 mol
at the second equivalence point means it is diprotic. the equation is given as :
H₂A + 2OH⁻ -----> H₂O + HA⁻
H₂A ---> 2H⁺ + A⁻
molarity of solution = 2 × 0.0072 / 0.035 L
= 0.411 M
Thus, a 35.00-ml sample of solution required 40.30 ml of 0.1823 m solution to titrate it to the second equivalence point. the molarity of the solution is 0.411 M.
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