The confidence interval for the true percent of car owners in the city who received a speeding ticket be, (139.27 , 160.73).
Subtract 1 from your sample size. 1000 – 1 = 999. This provides the degrees of freedom.
Subtract the confidence level from 1, and then divide by two.
(1 – .95) / 2 = .025
Now, df = 999 and α = 0.025
from the table at df = 999 we got 2.262.
Divide your sample standard deviation by the square root of your sample size.
150 / √(10) = 4.74
Now, 2.262 × 4.74 = 10.73
So, the confidence interval be,
(150 - 10.73 , 150 + 10.73) = (139.27 , 160.73)
Hence, the confidence interval for the true percent of car owners in the city who received a speeding ticket be, (139.27 , 160.73).
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