a hippogriff rancher wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle (see the figure below). he has 590 feet of fencing available to complete the job. what is the largest possible total area of the four pens?

Respuesta :

The largest area is found to be 8702.5 [tex]ft^{2}[/tex].

We know that area of rectangle

A = xy ........ (1)

Perimeter of rectangle (given) = 590 ft

Using x and y as two variables ;

5x + 2y = 590

solve yb in term of x

y = -5/2 x + 295......(2)

Now we will get area only in one variable from (1) and (2)

A = x ((-5/2)x + 295)

A = -5/2 [tex]x^{2}[/tex] + 295x

differentiate it with respect gto x

A' = -5x + 295........ (3)

find the critical point to get your minima and maxima value.

Put A' = 0,  x = 295/5 = 59

x = 59

then , from (2)

y= (-5/2 × 59) + 295 = 147.5

y = 147.5

again differentiate (3)

A'' = -5 < 0. i.e critical point x = 59 is point of maxima.

So, maximum area = 59 × 147.5

Largest area = 8702.5 [tex]ft^{2}[/tex]

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