we use is the derivative of top times bottom times top over bottom squared. At the critical point, we want eight X ln x minus four X to equal zero.
Only one answer—two x minus one and one x minus half—will satisfy the condition. The largest and smallest endpoints on the left and right must be determined. On each of these items, there is an E square root. A maximum for the minimums occurs at critical point or endpoints. We can see that these will be absolute according to the extreme value theorem, and here is our maximum.
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