The solution of a linear equation is (-2,5,4).
The equations given in the questions are,
x - y + 2z = 1 ..[1]
3x + y + 5z = 19 ..[2]
2x - y - 2z = -17 ...[3]
Putting the value of y from [1] in [2]and [3]
y = x+ 2z -1
3x + (x+ 2z -1) + 5z = 19
4x + 7z = 20 ...[4]
2x - (x+ 2z -1) - 2z = -17
x - 4z = -18 ...[5]
Solving equations [4] and [5] by substitution:
Putting values of x from [5] in [4]
x = 4z -14
4(4z -18) + 7z = 20
16z - 72+ 7z =20
23z = 92
z = 4
x = 4 × (92 ÷ 23) - 18
x = -2
y = (-2) + 2 × (92 ÷ 23) - 1
y = 5
(x,y,z) = (5.-2,4)
The solution of the equation is (-2,5,4).
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