contestada

A scuba diver fills her lungs to capacity (6.0 L) when 10.0 m below the surface of the water and begins to ascend to the surface. Assume the density of the water in which she is swimming is 1000 kg/{eq}m^3 {/eq} and use g = 10 m/{eq}s^2 {/eq}A. Assuming the temperature of the air in her lungs is constant, to what volume must her lungs expand when she reaches the surface of the water?B. What effect would the warming of the air in her lungs have on the volume needed when she surfaces?C. Assuming the temperature of the air in her lungs is constant, what effect does her ascent have on the vrms of the air molecules in her lungs?

Respuesta :

The lungs of the scuba diver should expand to a volume of 12L, the volume of the air will increase in her lungs with increase in temperature on the surface and the rms speed of the velocity of air will not change in her lungs.

The density of the water is given to be 1000 kg/m³. The capacity of the lungs of the diver is 6L and she goes down will 10m in the water. We can assume the temperature of the water to be constant.

A. The pressure P₁ at the surface of water is 100000 Pa.

So, the pressure at the depth of 10m in water will be given by,

P₂ = 1000x10x10 + P₁

P₂ = 100000 + P₁

P₂ = 200000 Pa

Now, we can write,

P₁V₁ = P₂V₂

Putting values,

6 x 200000 = V₂ x 100000

V₂ = 12L.

So, her lungs should expand to 12L.

B. On the surface, the pressure will be constant, so, the warming of air will further increase the volume of air in the lungs.

C. The Vrms is given by,

Vrms = √(3RT/M)

So, if the temperature is constant, the Vrms will not change because the mass of the air will also be the same.

To know more about Volume and pressure of gas, visit,

https://brainly.com/question/25736513

#SPJ4

Otras preguntas