contestada

A monatomic ideal gas is compressed at a constant pressure of 0.293 atm from a volume of 7.43 L to 3.32 L. In the process, heat energy flows out of the gas.
(a) What is the work done on the gas? Answer needs to be in J ( ± 2 J)
(b) What is the change in its internal energy? Answer needs to be in J ( ± 2 J)

Respuesta :

The work done on the gas is 2.73 Joules and the change in internal energy of the system is -2.73 Joules.

The monoatomic gas is taken from 7.43L to 3.32L at a constant pressure of 0.293 atm.

(a) The work done for monoatomic gas is,

W = PΔV/(1-y)

P is pressure, V is volume and y is adiabatic constant which is 1.66 for monoatomic gas.

Putting values,

W = 0.293(3.32-7.73)/-0.44

W = 2.73 Joules.

So, the work done in this process is 2.73 Joules.

(b) In this process the change in internal energy is negative to the work done so, Change in internal energy of the system is -2.73 Joules.

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