Respuesta :
To calculate the maximum speed of the Bugatti Veyron, we can use the equation $F_d = \frac{1}{2} \rho v^2 c A$,
which relates the drag force $F_d$ acting on an object to the density of the fluid $\rho$, the speed $v$ of the object, the drag coefficient $c$, and the cross-sectional area $A$ of the object.
In this case, we are given the mass of the car, the drag coefficient, and the force that the engine can impart on the road, so we can solve for the maximum speed.
First, we need to convert the mass of the car to its weight, which is the force of gravity acting on the car. The weight of the car is given by the equation $W = mg$, where $m$ is the mass of the car and $g$ is the acceleration due to gravity.
We can convert the mass of the car from kilograms to newtons by multiplying it by $g$, which is approximately 9.8 m/s$^2$. This gives us a weight of $W = 1834 \text{ kg} \times 9.8 \text{ m/s}^2 = 17983.2 \text{ N}$.
Next, we need to calculate the cross-sectional area of the car. Since we are given the shape of the car and the drag coefficient, we can assume that the car has a streamlined shape with a length $L$ that is much greater than its width or height.
In this case, the cross-sectional area of the car is approximately equal to its width $w$ times its height $h$, or $A \approx wh$. If we assume that the width of the car is $w = 1.8$ meters and the height is $h = 1.2$ meters, then the cross-sectional area is $A \approx 2.16 \text{ m}^2$.
Now that we have all of the required information, we can solve for the maximum speed of the car. The maximum speed is achieved when the drag force acting on the car is equal to the force that the engine can impart on the road. This means that the maximum speed $v_\text{max}$ is given by the equation
$F_d = \frac{1}{2} \rho v_\text{max}^2 c A = F_\text{engine}$
where $\rho$ is the density of the air, $c$ is the drag coefficient, $A$ is the cross-sectional area of the car, and $F_\text{engine}$ is the maximum force that the engine can impart on the road.
We are given that the drag coefficient is 0.342 kg/m and the maximum force that the engine can impart on the road is 4522 N. The density of the air is approximately 1.225 kg/m$^3$ at sea level. Plugging these values into the equation, we get
$\frac{1}{2} \times 1.225 \text{ kg/m}^3 \times v_\text{max}^2 \times 0.342 \text{ kg/m} \times 2.16 \text{ m}^2 = 4522 \text{ N}$
Solving for the maximum speed, we get $v_\text{max} \approx 242.5$ m/s. This is the maximum speed of the Bugatti Veyron if we neglect all other sources of friction and assume that the car has a streamlined.
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