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the left end of a long glass rod 9.00 cmcm in diameter, with an index of refraction 1.56, is ground and polished to a convex hemispherical surface with a radius of 4.50 cmcm . an object in the form of an arrow 1.49 mmmm tall, at right angles to the axis of the rod, is located on the axis 23.0 cmcm to the left of the vertex of the convex surface.Find the position and height of the image of the arrow formed by paraxial rays incident on the convex surface. Is the image erect or inverted?

Respuesta :

S' = 14.77 cm height of image = 0.577 mm is the computed response. It is inverted because magnification is negative.

Where radius (R) is positive because it is facing the same direction as the refracted light, and index of refraction (n1) = 1 for air and index of refraction for glass (n2) = 1.60, object distance from vertex to spherical surface (s) is 24 cm, or 0.24 meters, and image distance from vertex to spherical surface (s') is 4 cm, or 0.04 meters.

Height of object = y = 1.5 mm = 0.0015 m Height of image = y'

For a spherical reflecting surface, the object-image formula is:

According to the magnifying formula:

It is inverted because magnification is negative.

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