Respuesta :
The additive counterpart of given expressions are (2a+3b), -2a+2(-b+c), and -3(a+2b)+2c=0.
When two numbers may be added together or multiplied, regardless of the order in which they are entered, the result is said to be commutative. There are different formulas available for the conversion of multiplicative expressions to their additive counterparts.
a) The first expression is a²b³. This expression is written as aabbb. This is of the form ab and its corresponding additive counterpart is of the form a+b.
Then, a+a+b+b+b=2a+3b.
b) The second expression is a⁻²(b⁻¹c)². This expression is of the form a⁻¹ and its corresponding additive counterpart is of the form -a.
Then,
[tex]\begin{aligned}a^{-2}(b^{-1}c)^2&=a^{-1}a^{-1}(b^{-1}c)(b^{-1}c)\\&=-a-a-b+c-b+c\\&=-2a+2(-b+c)\end{aligned}[/tex]
c) The third expression is (ab²)⁻³c²=e. This expression is first expanded as, (ab²)⁻¹(ab²)⁻¹(ab²)⁻¹c²=e. Using property, (xy)⁻¹=y⁻¹x⁻¹.
Then,
[tex]\begin{aligned}\{(b^2)^{-1}a^{-1}\}\{(b^2)^{-1}a^{-1}\}\{(b^2)^{-1}a^{-1}\}c^2&=e\\\{b^{-2}a^{-1}\}\{b^{-2}a^{-1}\}\{b^{-2}a^{-1}\}c^2&=e\end{aligned}[/tex]
Also, the additive identity to e is zero. And, aⁿ=na.
Then,
{-2b-a}+{-2b-a}+{-2b-a}+2c=0
Simplifying we get,
-3(a+2b)+2c=0.
The complete question is -
Translate each of the following multiplicative expressions into its additive counterpart. assume that the operation is commutative
a. a²b³
b. a⁻²(b⁻¹c)²
c. (ab²)⁻³c²=e
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