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a majorette in a parade is performing some acrobatic twirlings of her baton. assume that the baton is a uniform rod of mass 0.120 kgkg and length 80.0 cmcm . figure1 of 1 part a initially, the baton is spinning about an axis through its center at angular velocity 3.00 rad/srad/s . (figure 1)what is the magnitude of its angular momentum about a point where the axis of rotation intersects the center of the baton? express your answer in kilogram meters squared per second.

Respuesta :

The magnitude of its angular momentum about a point where the axis of rotation intersects the center of the baton is  1.92*10^-2 kg*m^2/s and angular momentum of rod 7.68*10^-2 kg*m^2/s.

A)

Moment of inertia of rod = 1/12*m*L^2

= 1/12*0.12*0.8^2 = 0.0064

Angular momentum = I*ω

= 0.0064*3

= 0.0192 = 1.92*10^-2 kg*m^2/s

B)

Moment of inertia of rod = 1/3*m*L^2

= 1/3*0.12*0.8^2 = 0.0256

Angular momentum = 0.0256*3 =

00768 = 7.68*10^-2 kg*m^2/s

Learn more about angular momentum here:

https://brainly.com/question/15104254

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