You are watching an object that is moving in SHM. When the object is displaced 0.600 m to the right of its equilibrium position, it has a velocity of 2.20 m/s to the right and an acceleration of 8.40m/s2 to the left.How much farther from this point will the object move before it stops momentarily and then starts to move back to the left?

Respuesta :

The object move before it stops momentarily and other starts to move back to the left is 1.42m  to the right and an acceleration of 8.40m/s2.

using law of conservation of energy

Total energy at the 0.6 m = total energy at the right extreme position

(0.5*k*x^2) + (0.5*m*v^2) = (0.5*k*A^2)

F = -k*x

m*a = -k*x

force constant k = -m*a/x

then

(-0.5*m*a/x)*x^2 + (0.5*m*v^2) = -(0.5*m*a/x)*A^2

m cancels

(-0.5*8.4*0.6)+(0.5*2.2*2.2) = (-0.5*8.4/0.6)*A^2

-0.1 = -7*A^2

A = [tex]sqrt(10/7)[/tex]  = 1.42 m is the required distance

The rate at which an object's velocity changes in relation to time is known as acceleration. The direction of the net force imposed on an item determines its acceleration in relation to that force. According to Newton's Second Law, the magnitude of an object's acceleration is the result of two factors working together: The magnitude of the net balance of all external forces acting on the item is directly proportional to this net resultant force, whereas the mass of the object, depending on the materials used to make it, is inversely related to the magnitude.

Learn more about acceleration here:

https://brainly.com/question/13214928

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