Only one genuine zero exists, and it is found at x = 1.359. newton's method to approximate the zero(s) of the function
The first three decimal places were repeated in the solution after the fourth iteration. I began by assuming that x = 1 was the answer to the Newton's Method formula.
When I entered 1 for x, I received a zero of 5/3.
I entered 5/3 and repeated the process to get 997/687.
I was able to get 1.36976 by plugging in 997/687 and repeating the process.
I entered 1.36976 and repeated the process to get 1.359454.
I entered 1.359454 and repeated the process to get 1.359304.
There was no need to go any further because we are only interested in accuracy to three decimal places.
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