Respuesta :
A single wild type phenotype exhibits numerous mutations. Whether any of mutations affect just one gene, or if each mutation affects one of many genes required for expression of a phenotype.
The complementation test is the simplest way to separate the two possibilities. The test is straightforward to carry out; two mutants are crossed, and the F1 generation is examined. We infer that each mutation is in one of the two potential genes required for the wild type phenotype if the F1 exhibits the wild type phenotype. Alternatively, if the F1 exhibits a mutant phenotype rather than the wild-type phenotype, we infer that the two mutations are present in the same gene.
The mutant allele of gene A and the wild type allele of gene B, each supplied by one of the mutant parents, will both be expressed in the F1 when it is born. The F1 will also express the wild-type allele for gene A and the mutant allele for gene B provided by the other mutant parent. The wild type phenotype is shown because the F1 is expressing both of the required wild type alleles. A mutant form of the gene will be expressed by each homolog in the F1 if the mutations are in the same gene, on the other hand. A mutant phenotype develops in the absence of a normally functioning gene product in the individual.
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