According to given data find the test statistic for this test using Ha:
p1 = 0.581
p2 = 0.832
standard error = SE = 0.116
Z = [tex]\frac{p1 - p2}{SE}[/tex]
Z = [tex]\frac{0.581 - 0.832}{0.116}[/tex] = -2.164
Z = -2.164
p - value
it is left tailed test.
p - value for left tailed test is,
p - value = P(Z < test statistics )
p - value = P(Z < -2.164)
P - value = 0.015
confidence level = 95% = 0.95
significance level = α = 0.05
P -value is less than 0.05
so, reject null hypothesis at α = 0.05
That is [tex]P_{B}[/tex] < [tex]P_{NY}[/tex]
so, based on P - value , All values in the 95% confidence interval
PB - PNY is negative.
Reject null hypothesis at α = 0.05
so, [tex]P_{B}[/tex] < [tex]P_{NY}[/tex]
Hence, The proportion of Boston drivers wearing seat was significantly lower than the proportion of new York drivers wearing seat belts.
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