Nuclear decay occurs according to first-order kinetics. A nuclide decays in 3. 40 days from 45. 0 g to 12. 1 g. What is the rate constant for the nuclide?.

Respuesta :

The equilibrium law for the nuclide is 0.388 days per one, according to the announcement.

By nuclide, what do you mean?

  • Because nuclear decay reactions follow first-order kinetics and have a rate constant that is independent of temperature and the chemical or physical environment, we can perform similar calculations using the half-lives of isotopes to estimate the ages of geological and archaeological artifacts.
  • he fundamental difference between zero and first-order kinetics is their elimination rate compared to total plasma concentration. Zero-order kinetics undergo constant elimination regardless of the plasma concentration, following a linear elimination phase as the system becomes saturated
  • The first-order radioactive decay law states that the rate of decay (number of disintegrations per second) is proportional to the number of radioactive atoms (N) present at that time t. N = No e-λt.
  • The amount of protons, protons, and the activity state of nucleus determine the species of atom known as a nuclide, also known as a nuclear species. Thus, a nuclide is identified by its number of protons and mass number (A) (Z).
  • A nuclide is similar to but distinct from an atom or a nucleus. It has several nucleons, which define it. Nuclide, to put it simply, is a type of atom or nucleus. We characterize it using the elements that make up its nucleus, as well as the quantity of protons, neutron, and energy.
  • One-half of 24 grams is 12 grams, so 12 grams remained after the first 12 minutes.

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