7.87° is the first-order maximum for 550 nm.
Using diffraction equations,
d = 0.01/Number of lines, where 0.01 m = 1 cm and d = line spacing
Therefore,
d = 0.01/2070 = 4*10^-6 m
Similarly,
d x Sin X = m x Y;
When X = Angle
m = order = 1
Y = wavelength = 550 nm =550*10^-9 m
By substituting;
Sin X = mY / d = (1*550*10^-9)/(4*10^-6) = 0.1375
X = Sin⁻¹(0.1375) = 5.97°
As a result, the first-order maximum for 550 nm will be 7.87°.
To learn more about diffraction refer to :
https://brainly.com/question/8645206
#SPJ4