Respuesta :
The probability for observing the expected count will be given by [tex]E_i = nP_i[/tex]
Consider an experiment with n independent trials and k > 3 mutually incompatible outcomes.
Where [tex]P_i[/tex] stands for the likelihood of seeing the i-th result.
Hence for the nth expected result on i will be given by multiplying the i-th probability with the expected variable n.
Hence [tex]E_i = n\times P_i[/tex]
∴ [tex]E_i = nP_i[/tex] provides the predicted numbers for each potential outcome.
where pi is the likelihood of seeing the i-th result.
The predicted count of the i-th result is called [tex]E_i[/tex].
When two events cannot occur concurrently at the same moment, they are said to be mutually exclusive in accordance with probability theory. Or, to put it another way, discontinuous events are said to be mutually exclusive.
There is no possibility of two occurrences occurring simultaneously if they are viewed as separate events. If two events do not take place at the same time, they are said to be mutually exclusive. If a coin is tossed, the outcome will always be either head or tail; we cannot get both.
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