11 black balls and 14 white balls are placed in an urn. two balls are then drawn in succession. what is the probability that the second ball drawn is a white ball if the second ball is drawn without replacing the first ball? a) 0.2333 b) 0.5376 c) 0.5600 d) 0.2567 e) 0.3033 f) none of the above.

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

Given:

11 black balls and 14 white balls are placed in an urn. two balls are then drawn in succession.

We have to find the probability that the second ball drawn is a white ball if the second ball is drawn without replacing the first ball.

P(white ball) = 14 / (11 + 14) = 14 / 25

P(2nd ball is white) = P(first ball is white)*P(2nd ball is white) + P(first ball is black)*P(2nd ball is white)

= (14 / 25) * (13 / 24) + (11 / 25) * (14 / 24)

=0.56

Hence, the probability for the given condition is, 0.56.

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