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solid ammonium chloride, nh4cl, is formed by the reaction of gaseous ammonia, nh3, and hydrogen chloride, hcl. nh3(g) hcl(g)⟶nh4cl(s) a 4.98 g sample of nh3 gas and a 4.98 g sample of hcl gas are mixed in a 0.50 l flask at 25 ∘c. identify the limiting reagent. nh3 hcl nh4cl how many grams of nh4cl will be formed by this reaction? mass: g what is the pressure in atmospheres of the gas remaining in the flask? ignore the volume of solid nh4cl produced by the reaction.

Respuesta :

the mass of the resulting strontium fluoride precipitate is 2.27m.

What is mass?

massis quantitative measure of inertia,a fundamental property of all matter.

Sr(NO3)2(aq) +  2NaF(aq) ==> SrF2(s) + 2NaNO3  ...  balanced equation

moles Sr(NO3)2 = 0.180 L x 2.400 mol/L = 0.432 moles

moles NaF = 0.200 L x 3.088 mol/L = 0.6176 moles

NaF is LIMITING REACTANT b/c it takes 2 NaF per 1 Sr(NO3)2 and there isn't enough NaF.

Mass of Sr(NO3)2 precipitate = 0.6176 mol NaF x 1 mol SrF2 / 2 mol NaF x 125.6 g SrF2/mol = 38.8 g

Final volume = 180 ml + 200 ml = 380 ml = 0.380 L

[F-] = 0 since all the F- is precipitated as SrF2

[Sr2+] = 0.432 mol - 0.309 mol = 0.123 mol/0.380 L = 0.324 M

[Na+] = 0.6176 moles / 0.380 L = 1.63 M

[NO3-] = 0.432 moles x 2 = 0.864 mol/0.380 L = 2.27 M

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