Calculate the margin of error for a ampling ditribution that ha a ize of 36 for a 93% confidence level. The population tandard deviation i known to be 12

Respuesta :

The margin of error for a sampling distribution is found as 3.34.

Explain the term margin of error?

  • The margin of error, sometimes known as the confidence interval, provides information on how closely your survey results will likely reflect the opinions of the general community.
  • Keep in mind that conducting surveys requires you to strike a balance by using a smaller group (the survey respondents) to represent a much broader one.

Margin of error = z × σ/√n

  • n = sample size (36)
  • σ = population standard deviation  (12)
  • z = z-score

Thus, put the values;

z-score for 93% confidence level = 1.67

Margin of error = 1.67 ×12/√36

Margin of error = 3.34

Thus, the margin of error for a sampling distribution is found as 3.34.

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