Considering no change of pressure, the size of the gas at the high temp is 12.09L.
The equilibrium will move to the side where there are less moles of gas as pressure rises. The equilibrium will move toward the reactants side where there are more gas molecules when the pressure is reduced.
Briefing :
To solve this we assume that the hydrogen gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:
T1 / V1 = T2 / V2
V2 = T2 x V1 / T1
V2 = (100 + 273.15) K x 2.50 L / (-196 + 273.15) K
V2 = 12.09 L
Therefore, the volume would increase to 12.09 L as the temperature is increased to 100 degrees Celsius.
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