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Assume that a procedure yields a binomial distribution with a trial repeated n=5n=5 times. Use either the binomial probability formula (or a technology like Excel or StatDisk) to find the probability of k=1k=1 successes given the probability p=p=9/10 of success on a single trial.
(Report answer accurate to 4 decimal places.)
P(X=k)=

Respuesta :

By using Binomial Distribution, it can be calculated that -

P(X = 1) = 0.0005

What is Binomial Distribution?

Binomial distribution is a discrete type probability distribution whose probability density function is given by

P(X = x) = [tex]{n \choose x} p^xq^{n - x}[/tex]

Where p is the probability of success and q is the probability of failure

Here, Binomial Distribution of probability is used

k = 1

p = 0.9

q = 1 - 0.9 = 0.1

n = 5

P(X = 1) = [tex]{5 \choose 1} (0.9)^1(0.1)^{5 - 1}[/tex]

            = 0.00045

            = 0.0005

To learn more about Binomial Distribution , refer to the link-

https://brainly.com/question/9325204

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