Respuesta :

[tex]\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b\qquad\qquad \\\\[-0.35em] ~\dotfill\\\\ \log_a(2)=f\hspace{5em} \log_a(3)=g\hspace{5em}\log_a(5)=h \\\\\\ 2^f=a\hspace{8em}3^g=a\hspace{7em}5^h=a[/tex]