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2. For a projectile fired at 0° from a height of 19.6 m, how long does it take it to hit the ground? Remember that g = -9.8 m/s2. Initial velocity of the projectile is 40 m/s. Hint: Sine of 0° is 0 and Cosine of 0° is 1.

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ujalakhan18

Answer:

[tex]\huge\boxed{\sf T = 0 \ s}[/tex]

Explanation:

Formula for the time of flight of projectile:

[tex]\displaystyle T=\frac{2v_isin \theta}{g}[/tex]

Given that, θ = 0

So,

sin 0 = 0

[tex]\displaystyle T=\frac{2v_i(0)}{g} \\\\T = \frac{0}{g} \\\\T = 0 \ s\\\\\rule[225]{225}{2}[/tex]

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