Answer:
[tex]\huge\boxed{\sf h = six \ fifths}[/tex]
Step-by-step explanation:
[tex]\displaystyle \frac{1}{5} +h=\frac{7}{5} \\\\Subtract \ \frac{1}{5} \ to \ both \ sides\\\\h=\frac{7}{5} -\frac{1}{5} \\\\h = \frac{7-1}{5} \\\\h = \frac{6}{5} \\\\h = six \ fifths\\\\\rule[225]{225}{2}[/tex]