Dylan and Sophia are walking along Bluebird Lake on a perfectly calm day. Dylan, determined to impress Sophia by his ability to skip rocks, picks up the flattest rock he can find and gives it a sidearm launch from the edge of the water. The rock acquires a completely horizontal speed of 27.2 m/s from a height of 0.54 meters above the water surface. How far does it go horizontally before it hits the water?

Question 17 options:

0.3 meters

9.1 meters

0.1 meters

14.7 meters

The time of motion of the rock is the time taken for the rock to fall from the given height. The following kinematic equation will be used to determine the time of motion of the rock.

h = vt + ¹/₂gt²

where;

h is the height of fall
v is the vertical velocity = 0
t is the time of motion
g is acceleration due to gravity = 9.8 m/s²

h = ¹/₂gt²

t = √(2h/g)

t = √(2 x 0.54 / 9.8)

t = 0.33 s

The horizontal distance travelled by the rock before it hits the water is calculated as follows;

X = vt

where;

v is horizontal velocity
t is time of motion

X = 27.2 m/s x 0.33 s

X = 9.0 m

Learn more about horizontal distance here: brainly.com/question/24784992

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