Given,
The momentum of the object A before the collision, p₁ =80 Ns
The momentum of the object B before the collision, p₂=-30 Ns
Given that the objects stick together after the collision.
From the law of conservation of momentum, the total momentum of a system should always remain the same. Thus the total momentum of the objects before the collision must be equal to the total momentum of the objects after the collision.
Thus,
[tex]p_1+p_2=p[/tex]Where p is the total momentum of the system at any instant of time.
On substituting the known values,
[tex]\begin{gathered} p=80-30 \\ =50\text{ Ns} \end{gathered}[/tex]Therefore the total momentum of the system is 50 Ns
Thus the momentum of the object AB after the collision is 50 Ns
