Respuesta :
the coodrinates of JKLM is,
J(1,3) , K(3,1), L(-1,-3) and M(-3,-1)
the length JK is ,
[tex]\begin{gathered} JK=\sqrt[]{(1-3)^2+(3-1)^2} \\ =\sqrt[]{4+4} \\ =\sqrt[]{8} \\ =2\sqrt[]{2} \end{gathered}[/tex]length KL is,
[tex]\begin{gathered} KL=\sqrt[]{(-3-1)^2+(-1-3)^2} \\ =\sqrt[]{16+16} \\ =\sqrt[]{32} \\ =4\sqrt[]{2} \end{gathered}[/tex]Length LM is,
[tex]LM=\sqrt[]{(-3-(-1))^2+(-1-(-3))^2}[/tex][tex]\begin{gathered} LM=\sqrt[]{4+4} \\ LM=2\sqrt[]{2} \end{gathered}[/tex]length MJ
[tex]\sqrt[]{(-1-3)^2+(-3-1)^2}[/tex][tex]\begin{gathered} MJ=\sqrt[]{16+16} \\ MJ=4\sqrt[]{2} \end{gathered}[/tex]so, the perimeter = sum of sides,
= JK + KL + LM + MJ
= 2 root 2 + 4root2 + 2root2 + 4root2
= 12 root 2
thus, the perimeter is 12 root 2
