Respuesta :
The probability of a parallel park in the 5th spot out of 6 random arrangements is 2 ÷ 5.
The probability of the need to parallel park equal to the probability of 2 open spaces in the first 5 spots and not together equals the number of 2 possible open spots in the first 5 and not together ÷ The number of 2 possible open spots = (The number of 2 possible open spots in the first 5 - The number of 2 possible open spots together in the first 5) ÷ The number of 2 possible open spots.
The number of 2 possible open spots in the first 5 = nCr = C(5,2) = 10
The number of 2 possible open spots together in the first 5 = 4
The number of 2 possible open spots = nCr = C(6,2) = 15
The probability of the need to parallel park = (10 - 4) ÷ 15
= 6 ÷ 15
= 2 ÷ 5
To learn more about probability at
https://brainly.com/question/11234923?referrer=searchResults
#SPJ4
