The magnitude of the magnetic flux through each coil when the current is 4.00A is 15.58 T.m²
N = 527 turn
Δi/Δt = 10.0 A/s
ϵ = 19.0 mV = 19 x 10⁻³ V
I = 4.60 A
From ϵ = L(Δi/Δt), we have:
ϵ = L(Δi/Δt)
19 x 10⁻³ V = L (10.0 A/s)
L = 19 x 10⁻³V/10.0 A/s
L = 19 x 10⁻² H
From L = NΦ/I, we have:
Φ = Li/N
Φ = 19 x 10⁻² H (4.60 A)/527
Φ = 15.58 μT.m²
So, the magnitude of the magnetic flux is 15.58 T.m²
Learn more about magnetic flux at https://brainly.com/question/14411049
#SPJ4
