A triangle has vertices at F(-10,6)E(12,6),andD(2,-8). it is dilated by a scale factor of 1/2 with the origin as the center of dilation to form a similar triangle. What are the coordinates of the vertices of the image?

ANSWER
F' (-5, 3)
E' (6, 3)
D' (1, -4)
EXPLANATION
We are given the cordinates of the triangle as:
F(-10, 6), E(12, 6) and D(2, -8)
The dilation factor is 1/2.
To find the new cordinates, we simply multiply the cordinates of the triangle given by 1/2.
That is:
[tex]\begin{gathered} F^{\prime}\text{ = }\frac{1}{2}(-10,\text{ 6) = (}\frac{1}{2}\cdot\text{ -10, }\frac{1}{2}\cdot\text{ 6)} \\ F^{\prime}\text{ = (-5, 3)} \\ E^{\prime}\text{ = }\frac{1}{2}(12,\text{ 6) = (}\frac{1}{2}\cdot\text{ 12, }\frac{1}{2}\cdot\text{ 6)} \\ E^{\prime}\text{ = (6, 3)} \\ D^{\prime}\text{ = }\frac{1}{2}(2,\text{ -8) = (}\frac{1}{2}\cdot\text{ 2, }\frac{1}{2}\cdot\text{ -8)} \\ D^{\prime}\text{ = (1, -4)} \end{gathered}[/tex]So, the cordinates of the image are:
F' (-5, 3)
E' (6, 3)
D' (1, -4)