Respuesta :

[tex]\begin{gathered} f(x)=4x^2-9 \\ f(x)=(2x+3)(2x-3) \\ (2x+3)(2x-3)=0 \\ 2x+3=0 \\ 2x=-3 \\ x=\frac{-3}{2} \\ 2x-3=0 \\ 2x=3 \\ x=\frac{3}{2} \\ Hence \\ The\text{ solution is x=}\pm\frac{3}{2} \end{gathered}[/tex]

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