Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a queen and then without replacement a face card?express your answer as a fraction or decimal rounded to four decimal places

In this case, we'll have to carry out several steps to find the solution.
Step 01:
data:
total cards = 52
Step 02:
probability:
p(event) = favorable outcomes / total outcomes
total cards = 52
total queens = 4
total face cards = 12
first event (queen):
p(queen) = 4 / 52
second event (face card):
without replacement
p(face card) = 11 / 51
total probability (queen and face card):
[tex]p(queen\text{ }and\text{ }face\text{ }card)=\frac{4}{52}*\frac{11}{51}=\frac{44}{2652}=0.0166[/tex]The answer is:
p (queen and face card) = 0.0166