Respuesta :
Answer:
-239.13kJ/mol
Explanations:
The complete chemical reaction between the sodium metal and hydrochloric acid is expressed as shown:
[tex]2Na(s)+2\text{HCl(aq)}\rightarrow2NaCl(aq)+H_2(g)[/tex]The enthalpy of the reaction is expressed using the formula;
[tex]\triangle H^0_{rxn}=\frac{Quantity\text{ of h}eat}{Moles\text{ of sodium}}[/tex]Given that quantity of energy released is -2090J (Since energy is released by the system)
Get the moles of sodium
[tex]\begin{gathered} Moles\text{ of sodium =}\frac{Mass\text{ of Na}}{Molar\text{ mass of Na}} \\ \text{Moles of sodium =}\frac{0.201g}{22.99\text{g/mol}} \\ \text{Moles of sodium = }0.00874\text{moles of Na} \end{gathered}[/tex]Next is to get the required enthalpy of the reaction in kJ/mol
[tex]\begin{gathered} \text{Enthalpy of the reaction = }\frac{-2.090kJ}{0.00874\text{mol}} \\ \text{Enthalpy of the reaction = -}239.13\text{kJ/mol} \end{gathered}[/tex]Hence the enthalpy of the reaction is -239.13kJ/mol
