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For the reaction represented by the equation N2 + 3H, -> 2NH3, how many moles of nitrogen are required toproduce 18 mol of ammonia?

Respuesta :

Answer:

9moles of N2

Explanations:

Given the reaction represented by the equation:

[tex]N_2+3H_2\rightarrow2NH_3[/tex]

Given the following parameters

• Moles of ammonia = 18 moles

According to stoichiometry, 1 mole of nitrogen produces 2 moles of ammonia. Therefore the moles of nitrogen required is given as:

[tex]\begin{gathered} moles\text{ of }N_2=\frac{1mole\text{ of }N_2}{2\cancel{moles\text{ of }NH_3}}\times18\cancel{moles\text{ of }NH_3} \\ moles\text{ of }N_2=9moles \end{gathered}[/tex]

Hence the moles of nitrogen required to produce 18 mol of ammonia is 9moles

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