How many pounds of candy that sells for $0.85 per lb must be mixed with candy that sells for $1.22 per lb to obtain 9 lb of a mixture that should sell for $0.92 per lb? $0.85-per-lb candy

Respuesta :

Let us call x the number of lbs of $0.85 candy and y the number of lbs of $1.22 candy. The total number that x and y should add to is 9 lbs; therefore, we have

[tex]\textcolor{#FF7968}{x+y=9}[/tex]

The amount of money x lbs of $0.85 candy and y the number of lbs of $1.22 candy make together is

[tex]0.85x+1.22y[/tex]

This amount divided by 9 lb should give us $0.92/ lb; therefore, we have

[tex]\frac{0.85x+1.22y}{9}=0.92[/tex][tex]\textcolor{#FF7968}{\rightarrow0.85x+1.22y=8.28.}[/tex]

Hence, we have two equations with two unknown and all we need to do to find them is to solve the system.

The solution to the system turns out to be

[tex]x=7.2972[/tex][tex]y=1.70[/tex]

Hence, 7.2972 lb of $0.85 candy must be mixed with $1.70 lb candy to obtain a 9lb mixture that sells for $0.92 per lb.