To solve the exercise, let us first draw the rectangle:
The formula to find the area of a rectangle is
[tex]\begin{gathered} A=l\cdot w \\ \text{ Where } \\ A\text{ is the area,} \\ l\text{ is the length and} \\ w\text{ is the width of the rectangle} \end{gathered}[/tex]So, in this case, you have
[tex]\begin{gathered} l=12\text{ in} \\ w=7\text{ in} \\ A=l\cdot w \\ A=12\text{ in}\cdot7\text{ in} \\ A=84in^2 \end{gathered}[/tex]On the other hand, the perimeter is the sum of all the sides of a geometric figure. Then, in this case, you have
[tex]\begin{gathered} P=12\text{ in }+7\text{ in }+12\text{ in }+7\text{ in} \\ P=38\text{ in} \end{gathered}[/tex]Therefore, the perimeter and area of this rectangle are:
[tex]\begin{gathered} A=84in^2 \\ P=38\text{ in} \end{gathered}[/tex]
