Since the paper basked has a shape of a cone we need to use the correct formula for the surface area of a cone. This is shown below:
[tex]A_{surface}=\pi r(s+r)[/tex]Where r is the measurement of the radius and s is the measurement of the slant height. Applying the provided data from the problem we have:
[tex]\begin{gathered} A_{\text{surface}}=\pi\cdot\frac{5}{2}\cdot(8+\frac{5}{2}) \\ A_{\text{surface}}=\pi\cdot\frac{5}{2}\cdot(\frac{21}{2})=\frac{105}{4}\pi=82.47_{} \end{gathered}[/tex]The surface area of the basket is 105/4 pi square inches or 82.47 square inches.
