Determine the length of side AE.
[tex]\begin{gathered} AE=\frac{2}{3}AD \\ =\frac{2}{3}\cdot7.5 \\ =5 \end{gathered}[/tex]So length of side BD is equal to 5 cm.
Determine the length of side AB.
[tex]\begin{gathered} (AB)^2=(7.5)^2+(5)^2 \\ =56.25+25 \\ =81.25 \\ AB=\sqrt[]{81.25} \\ \approx9.01 \end{gathered}[/tex]The length of side AB and AC is equal so,
[tex]AC=9.01[/tex]Determine the perimeter of triangle.
[tex]\begin{gathered} P=2\cdot5+9.01+9.01 \\ =10+18.02 \\ =28.02 \end{gathered}[/tex]So perimeter of triangle is equal to 28.02 cm.
