The product of slople of two lines wchich are perpendicular to each other is negetive one.
The given expression of the line is,
[tex]y=-2x[/tex]The general expression for a stright line with slope 'm' is,
[tex]y=mx+c[/tex]Here, 'm' is the slope and 'c' is a constant.
Conparing the given equation of line with the general expression of a stright line,
[tex]m=-2[/tex]Thus, the slope of the given line is -2.
Let the slope of the perpendicular line to the given line be 'k'. Since the product of slope of perpendicular line is -1.
[tex]\begin{gathered} m\times k=-1 \\ k=\frac{-1}{k} \end{gathered}[/tex]Substitute value of m=-2 in the above expression.
[tex]\begin{gathered} k=\frac{-1}{-2} \\ k=\frac{1}{2} \end{gathered}[/tex]Thus, the slope of the perpendicular line is -1/2, and thus Dyne's statement is wrong.